Menampilkan JSON Random Postingan Blogger Menggunakan JQUERY

Contoh Kode JQUERY Random Post Blogger :

<li id="result"></li>

<script type="text/javascript">
var randarray = new Array();
var l=0;
var flag;
var numofpost=1;
function randomposts(json){
var total =parseInt(json.feed.openSearch$totalResults.$t,10);
for(i=0;i < numofpost;)
{flag=0;randarray.length=numofpost;l=Math.floor(Math.random()*total);
for(j in randarray){
if(l==randarray[j]){ flag=1;
}}
if(flag==0&&l!=0){randarray[i++]=l;
}}

for(n in randarray){ 
var p=randarray[n];
var entry=json.feed.entry[p-1];
for(k=0; k < entry.link.length;k++){if(entry.link[k].rel=='alternate'){
var item = "<li>" + "<a href=" + entry.link[k].href + ">" + entry.title.$t + "</a> </li>";
$('#result').html(item);
}}}

}
</script>
<script src="http://masterz-seo.blogspot.com/feeds/posts/default?alt=json-in-script&start-index=1&max-results=100&callback=randomposts" type="text/javascript"></script>

Smoga bermanfaat untuk sobat semua...
Previous
Next Post »